document.write( "Question 1141934: Two buses leave towns 580 miles
\n" ); document.write( " apart at the same time and travel toward each other. One bus travels 19 mi/h
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\n" ); document.write( " slower than the other. If they meet in 4
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Algebra.Com's Answer #762574 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+s+\" = the speed of the faster bus
\n" ); document.write( "\"+s+-+19+\" = the speed of the slower bus
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\n" ); document.write( "This is the same as if one of the buses travels at
\n" ); document.write( "the sum of their speeds for the entire distance, so
\n" ); document.write( "\"+580+=+%28+s+%2B+s+-+19+%29%2A4+\"
\n" ); document.write( "\"+145+=+2s+-+19+\"
\n" ); document.write( "\"+2s+=+164+\"
\n" ); document.write( "\"+s+=+82+\"
\n" ); document.write( "and
\n" ); document.write( "\"+s+-+19+=+63+\"
\n" ); document.write( "The speed of the faster bus is 82 mi/hr
\n" ); document.write( "The speed of the slower bus is 63 mi/hr
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\n" ); document.write( "check:
\n" ); document.write( "\"+d%5B1%5D+=+63%2A4+\"
\n" ); document.write( "\"+d%5B1%5D+=+252+\"
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+82%2A4+\"
\n" ); document.write( "\"+d%5B2%5D+=+328+\"
\n" ); document.write( "--------------------
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+252+%2B+328+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+580+\" mi
\n" ); document.write( "OK
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