document.write( "Question 1141917: What are the solutions of sin (x - π) + 2 = 1 in [0, 2π)? \n" ); document.write( "
Algebra.Com's Answer #762564 by ikleyn(52933)\"\" \"About 
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document.write( "\"sin%28x-pi%29+%2B+2%7D%7C%7D%7D+=+1+++====%3E%0D%0A%0D%0A%0D%0A%7B%7B%7Bsin%28x-pi%29\" = 1 - 2 = -1  ====>\r\n" );
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document.write( "\"x+-+pi\" = \"%283%2F2%29%2Api+%2B+k%2Api\",  where k is any integer . . . ====>\r\n" );
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document.write( "x = \"%283%2F2%29%2Api+%2B+%28k%2B1%29%2Api\",  where k is any integer . . . \r\n" );
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document.write( "    And now my task is to choose \"k\" in a way to provide  x = \"%283%2F2%29%2Api+%2B+%28k%2B1%29%2Api\"  in the interval  [\"0\",\"2pi\").\r\n" );
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document.write( "For it, take k = -2;  you will get  x = \"%283%2F2%29%2Api+-+pi\" = \"pi%2F2\".\r\n" );
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document.write( "ANSWER.  The solution is  x = \"pi%2F2\".\r\n" );
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document.write( "         This solution is unique.\r\n" );
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