document.write( "Question 1141833: Referring to the information below, what is the probability that he will receive at least three calls?\r
\n" ); document.write( "\n" ); document.write( "The probabilities that a doctor's answering service will receive 0, 1, 2, 3, 4, 5, 6, or 7 calls for him during lunch hour are, respectively, 0.001, 0.006, 0.022, 0.052, 0.091, 0.128, 0.149, and 0.551. \n" ); document.write( "

Algebra.Com's Answer #762470 by ikleyn(52863) $\"\"$ $\"About$

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document.write( "First, I checked that the given sequence P(0), P(1), P(2), P(3), P(4), P(5), P(6), P(7) of 8 terms monotonically increases \r\n" );
document.write( "and that the sum of all 8 (eight) given probabilities in the post is equal to 1 :\r\n" );
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document.write( "    0.001 + 0.006 + 0.022 + 0.052 + 0.091+ 0.128 + 0.149 + 0.551 = 1,\r\n" );
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document.write( "so the given data makes sense.\r\n" );
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document.write( "Second, the answer to the question is the sum of the last 5 (five) terms of the sequence\r\n" );
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document.write( "    P(the number of phone calls is at least 3) = P(3) +  P(4)  + P(5)  + P(6)  + P(7) = \r\n" );
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document.write( "                                               = 0.052 + 0.091 + 0.128 + 0.149 + 0.551 = 0.971.      ANSWER\r\n" );
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