document.write( "Question 1141826: Among a certain population of primates, the volume of the cranial cavity is normally distributed with a mean of 1000 cc and a standard deviation of 117 cc.
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document.write( "(a) What percentage of primates will have a volume of the cranial cavity smaller than 950
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document.write( "(b) What percentage of primates will have a volume of the cranial cavity between 1000 cc
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document.write( "and 1350 cc?
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document.write( "(c) What percentage of primates will have a volume of the cranial cavity larger than 1250
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document.write( "(d) We are selecting five members of this population at random. What is the probability that
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document.write( "all of the 5 selected primates will have a volume of the cranial cavity that is larger than
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document.write( "1150 cc? \n" );
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Algebra.Com's Answer #762464 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd or (x bar-mean)sigma/sqrt(n) if a sample is used \n" ); document.write( "a. z<(950-1000)/117 or <-0.43 and that probability is 0.3336 \n" ); document.write( "b. this is z between 0 and 350/117 or between 0 and 3 or 0.4986 probability \n" ); document.write( "c. greater than 1250 cc is z>250/117 or 2.14 for a probability of 0.0162 \n" ); document.write( "d. here it is z>(150/117)*sqrt(5) or z>2.87 or probability of 0.0021 \n" ); document.write( " |