document.write( "Question 1141814: the average score of all golfers for a particular course has a mean of 76 and a standard deviation of 5. Suppose 100 golfers played the course today. Fund the probability that the average score of 100 golfers exceeded 77. \n" ); document.write( "
Algebra.Com's Answer #762459 by Boreal(15235)\"\" \"About 
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z=(x bar-mean)/sigma/sqrt(n)
\n" ); document.write( ">=(77-76)/5/sqrt(100)
\n" ); document.write( ">=1*10/5
\n" ); document.write( ">=2
\n" ); document.write( "That probability is 0.0228
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