document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141739>Question 1141739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: Thirty percent of consumers prefer to purchase electronics online. You randomly select 8 consumers. Find the probability that the number of consumers who prefer to purchase electronics online is (a) exactly five, more than five, and (c) at most five.\r<BR>\n" );
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document.write( "Please email back at mkirkwood@windstream.net </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #762367 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=762367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use Binomial Probability Formula<BR>\n" );
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document.write( "Probability (P) (k successes in n trials) = nCk * p^k * (1-p)^(n-k), where p is the probability of success, nCk = n!/(k! * (n-k)!)<BR>\n" );
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document.write( "For this problem, n = 8, p = 0.30<BR>\n" );
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document.write( "(a)  P(exactly 5 consumers prefer to purchase electronics online) = 8C5 * (0.30)^5 * (1-0.30)^(8-5) = 0.0467 is approximately 0.05<BR>\n" );
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document.write( "(b) P(more than 5 consumers prefer to purchase electronics online) = summation from k = 6, 8 of P(k successes in 8 trials) = 0.0113 is approximately 0.01<BR>\n" );
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document.write( "(c) P(at most 5 consumers prefer to purchase electronics online) = 1 - P(more than 5 consumers prefer to purchase electronics online) = 1 - 0.01 = 0.99<BR>\n" );
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