document.write( "Question 1141747: In a dog park, there are 84 total legs. If there are 3 more dogs in the park than people, how many dogs are in the park? \n" ); document.write( "
Algebra.Com's Answer #762366 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "(1) Formally, using algebra....

\n" ); document.write( "The thing we are to find is the number of dogs, so let that be our variable:

\n" ); document.write( "let x = # of dogs
\n" ); document.write( "then x-3 = # of people

\n" ); document.write( "The total number of legs -- 4 per dog and 2 per person -- is 84:

\n" ); document.write( "\"4%28x%29%2B2%28x-3%29+=+84\"
\n" ); document.write( "\"4x%2B2x-6+=+84\"
\n" ); document.write( "\"6x+=+90\"
\n" ); document.write( "\"x+=+15\"

\n" ); document.write( "The number of dogs is 15.

\n" ); document.write( "(2) Informally, using logical reasoning and mental arithmetic....

\n" ); document.write( "(a) Add 3 more people, making the numbers of people and dogs the same. That brings the total number of legs to 84+6 = 90.
\n" ); document.write( "(b) Each dog-person pair has a total of 6 legs.
\n" ); document.write( "(c) Therefore, the number of dogs in the park is 90/6 = 15.
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