document.write( "Question 1141747: In a dog park, there are 84 total legs. If there are 3 more dogs in the park than people, how many dogs are in the park? \n" ); document.write( "

Algebra.Com's Answer #762363 by ikleyn(52786) $\"\"$ $\"About$

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document.write( "    4d + 2p = 84     (1)     (counting legs)\r\n" );
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document.write( "     d -  p =  3     (2)     (counting heads)\r\n" );
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document.write( "where \"d\" is the number of dogs and \"p\" is the number of people.\r\n" );
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document.write( "From eq(2) express p = d - 3  and substitute it into eq(1). You will get\r\n" );
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document.write( "    4d + 2*(d-3) = 84\r\n" );
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document.write( "    6d - 6 = 84\r\n" );
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document.write( "    6d = 84 + 6 = 90\r\n" );
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document.write( "    d = 90/6 = 15.\r\n" );
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document.write( "ANSWER.  15 dogs.\r\n" );
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