document.write( "Question 1141736: Find the lateral area of a regular square pyramid with base edge 6 cm and lateral edge 5 cm.\r
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Algebra.Com's Answer #762351 by ikleyn(52803) $\"\"$ $\"About$

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document.write( "Consider any of four lateral faces.\r\n" );
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document.write( "It is an isosceles triangle.\r\n" );
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document.write( "Draw the height in this triangle to the base.\r\n" );
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document.write( "You will get a right angled triangle, whose hypotenuse is 5 cm and one of legs is 3 cm (the half of 6 cm).\r\n" );
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document.write( "Hence, the other leg of this right-angled triangle is 4 cm  (3-4-5 right angled triangle).\r\n" );
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document.write( "Thus the lateral height of the face triangle is 4 cm.\r\n" );
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document.write( "Then the area of one (of each) face triangle is   = 12 square centimeters.\r\n" );
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document.write( "Hence, the lateral surface area of the pyramid is 4 times 12 square centimeters, i.e. 48 cm^2.    ANSWER\r\n" );
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