document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141733>Question 1141733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the lateral area of a cylinder with height 4 ft and radius 4 ft.<BR>\n" );
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document.write( "a. 16ft^2<BR>\n" );
document.write( " b. 32 ft^2<BR>\n" );
document.write( " c.16(pi sign) ft^2<BR>\n" );
document.write( " d. 32 (pi sign)ft^2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #762339 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=762339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Think of the cylinder as a can with the top and bottom cut out and then cut down the side and flattened out.  The lateral surface area of the cylinder will be a rectangle; its length will be the circumference of the cylinder and the width will be the height of the cylinder.  So<br><BR>\n" );
document.write( "surface area = (circumference of cylinder)*(height of cylinder) = (2(pi)r)*(h)<br><BR>\n" );
document.write( "Plug in the given radius and height.... </SPAN>\n" );
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