document.write( "Question 1141716: a square is inscribed in a circle. If the area of the circle is 25π sq. mm, what is the area of the square? \n" ); document.write( "
Algebra.Com's Answer #762323 by josmiceli(19441)\"\" \"About 
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The diagonal of the square will be the same as
\n" ); document.write( "the diameter of the circle
\n" ); document.write( "\"+A+=+25pi+\"
\n" ); document.write( "\"+A+=+pi%2Ar%5E2+\"
\n" ); document.write( "\"+25pi+=+pi%2Ar%5E2+\"
\n" ); document.write( "\"+r%5E2+=+25+\"
\n" ); document.write( "\"+r+=+5+\"
\n" ); document.write( "This is half the diameter, so
\n" ); document.write( "diameter = \"+10+\", and the
\n" ); document.write( "diagonal also = \"+10+\"
\n" ); document.write( "----------------------------------
\n" ); document.write( "Let \"+x+\" = a side of the square
\n" ); document.write( "For a square
\n" ); document.write( "\"+10+=+sqrt%282%29%2Ax+\"
\n" ); document.write( "\"+x+=+10%2Fsqrt%282%29+\"
\n" ); document.write( "\"+x+=+10%2Asqrt%282%29+%2F+2+\"
\n" ); document.write( "\"+x+=+5%2Asqrt%282%29+\"
\n" ); document.write( "and
\n" ); document.write( "Area of square = \"+x%5E2+\"
\n" ); document.write( "\"+x%5E2+=+25%2A2+\"
\n" ); document.write( "\"+x%5E2+=+50+\" mm2
\n" ); document.write( "get a 2nd opinion if needed
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