document.write( "Question 1141714: A parallelogram has vertices at (4,2), (10,2), (8,9) and (14,9). What is the area of the parallelogram? \n" ); document.write( "
Algebra.Com's Answer #762318 by ikleyn(52906) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "The parallelogram has vertices at A = (4,2), B = (10,2), C = (8,9) and D = (14,9). \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The sides AB and CD are horizontal and have the length of 7 = 9-2 units.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Vertical dimension (the height) of the parallelogram has the measure of 7 units.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hence, the area of the parallelogram is the product 6*7 = 42 square units. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |