document.write( "Question 1141704: write a cosine function with amplitude 3 and period pi/2 which has been shifted up 1 unit.\r
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Algebra.Com's Answer #762301 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "With no horizontal shift, a general cosine function is

\n" ); document.write( "\"f%28x%29+=+a%2Acos%28bx%29%2Bd\"

\n" ); document.write( "where a is the amplitude, b determines the period, and d is the vertical shift.

\n" ); document.write( "In this problem the amplitude is 3 and the vertical shift is +1, so the equation is

\n" ); document.write( "\"f%28x%29+=+3%2Acos%28bx%29%2B1\"

\n" ); document.write( "To find the value of the parameter b, note that the basic cosine function has a period of 2pi while the given function has a period of pi/2. That means the function completes 4 cycles from 0 to 2pi; that means b is 4.

\n" ); document.write( "(Algebraically, b is equal to 2pi divided by the period; in this example, (2pi)/(pi/2) = 4.)

\n" ); document.write( "So

\n" ); document.write( "\"f%28x%29+=+3%2Acos%284x%29%2B1%29\"
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