document.write( "Question 1141500: premise (P&Q)V(R&S)
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document.write( "Premise R->L
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document.write( "goal ~P->L \n" );
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Algebra.Com's Answer #762278 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "1. (P & Q) V (R & S)\r\n" ); document.write( "2. R -> L / ~P -> L\r\n" ); document.write( "\r\n" ); document.write( " | 3. ~P assumption for conditional proof\r\n" ); document.write( " | 4. ~P V ~Q 3. addition\r\n" ); document.write( " | 5. ~(P & Q) 4. deMorgan's law\r\n" ); document.write( " | 6. R & S 1,5, disjunctive syllogism\r\n" ); document.write( " | 7. R 6, simplification\r\n" ); document.write( " | 8. L 2,7, modus ponens\r\n" ); document.write( "\r\n" ); document.write( "8. ~P -> L lines 3-8 for conditional proof.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |