document.write( "Question 104654This question is from textbook
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document.write( ": W x (L=9) = 36 2\r
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document.write( "length is 9 inches greater than the width area 36in2.
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document.write( "Can you please break down how this is done (the formula).
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document.write( "Thank you \n" );
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Algebra.Com's Answer #76226 by Fombitz(32388) You can put this solution on YOUR website! The area of a rectangle is equal to A=L*W. \n" ); document.write( "The area of your rectangle is 36 sq.inches. \n" ); document.write( "Your first equation is \n" ); document.write( "1. \n" ); document.write( "You say that the length is 9 inches greater than the width, or \n" ); document.write( "2. \n" ); document.write( "Substitute your equation (2) into (1) and solve for W. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Solutions are \n" ); document.write( "W=-12, W=3. \n" ); document.write( "Since a negative width does not make sense, we throw out that solution. \n" ); document.write( "W=3 inches \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "L=12 inches \n" ); document.write( " |