document.write( "Question 104654This question is from textbook
\n" ); document.write( ": W x (L=9) = 36 2\r
\n" ); document.write( "\n" ); document.write( "length is 9 inches greater than the width area 36in2.
\n" ); document.write( "Can you please break down how this is done (the formula).
\n" ); document.write( "Thank you
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Algebra.Com's Answer #76226 by Fombitz(32388)\"\" \"About 
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The area of a rectangle is equal to A=L*W.
\n" ); document.write( "The area of your rectangle is 36 sq.inches.
\n" ); document.write( "Your first equation is
\n" ); document.write( "1. \"A=LW=36\"
\n" ); document.write( "You say that the length is 9 inches greater than the width, or
\n" ); document.write( "2.\"L=9%2BW\"
\n" ); document.write( "Substitute your equation (2) into (1) and solve for W.
\n" ); document.write( "\"LW=36\"
\n" ); document.write( "\"%289%2BW%29W=36\"
\n" ); document.write( "\"9W%2BW%5E2=36\" Distributive property.
\n" ); document.write( "\"W%5E2%2B9W-36=0\" Additive inverse of 36.
\n" ); document.write( "\"%28W%2B12%29%28W-3%29=0\" Factor the quadratic equation.
\n" ); document.write( "Solutions are
\n" ); document.write( "W=-12, W=3.
\n" ); document.write( "Since a negative width does not make sense, we throw out that solution.
\n" ); document.write( "W=3 inches
\n" ); document.write( "\"L=9%2BW\"
\n" ); document.write( "\"L=9%2B3\"
\n" ); document.write( "L=12 inches
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