document.write( "Question 104740: 50. Solve each system by substitution or addition, whichever is easier.\r
\n" ); document.write( "\n" ); document.write( "2y-x=3
\n" ); document.write( " x=3y-5\r
\n" ); document.write( "\n" ); document.write( "What are the steps to solving this problem? \n" ); document.write( "
Algebra.Com's Answer #76222 by doukungfoo(195)\"\" \"About 
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2y-x=3
\n" ); document.write( "x=3y-5
\n" ); document.write( "Since the second equation has already been set equal to x I'll demostrate the substitution method.
\n" ); document.write( "Substitute 3y-5 for x in the first equation
\n" ); document.write( "2y - x = 3
\n" ); document.write( "2y - (3y-5) = 3
\n" ); document.write( "2y - 3y + 5 = 3
\n" ); document.write( "-1y + 5 = 3
\n" ); document.write( "-y = -2
\n" ); document.write( "y = 2
\n" ); document.write( "Now use this value for y to solve for x in the second equation
\n" ); document.write( "x = 3y - 5
\n" ); document.write( "x = 3(2) - 5
\n" ); document.write( "x = 6 - 5
\n" ); document.write( "x = 1
\n" ); document.write( "Check both anwsers in both equations
\n" ); document.write( "Try the first equation
\n" ); document.write( "2y - x = 3
\n" ); document.write( "2(2) - (1) = 3
\n" ); document.write( "4 - 1 = 3
\n" ); document.write( "3 = 3
\n" ); document.write( "Now try the second equation
\n" ); document.write( "x = 3y - 5
\n" ); document.write( "1 = 3(2) - 5
\n" ); document.write( "1 = 6 - 5
\n" ); document.write( "1 = 1
\n" ); document.write( " \n" ); document.write( "
\n" );