document.write( "Question 1141623: A box contains 24 pieces of fruit: 7 cherry, 8 orange and 9 lemon. If no cherries are sold, what is the minimum number of lemons that can be sold in order to increase the probability of picking out a cherry to 50%?
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document.write( "A)0
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document.write( "B)1
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document.write( "C)2
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document.write( "D)3 \n" );
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Algebra.Com's Answer #762219 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Unfortunately none of these choices work. Let's go through them one by one to see why. \r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So there seems to be a typo with this problem. Please ask your teacher for clarification and/or corrections. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side note: If we sold all 9 lemons, then the only way to have a 50% shot at getting a cherry is that we must have the same number of cherries and oranges. The fact that we have 7 cherries and 8 oranges means that the chances of picking a cherry are less than 50%. This is because there are less cherries compared to oranges. \n" ); document.write( " \n" ); document.write( " |