document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104718>Question 104718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I have been struggling all morning with a problem.  Here it is:<BR>\n" );
document.write( "The length of a rectangle is 1 less than twice its width.  If the width is 3 more than one-seventh of the perimeter, find the dimensions of the rectangle.  \r<BR>\n" );
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document.write( "While I can come up with a value for P which is a term, not a value, I cannot come up with any actual dimensions, and my answer will not proof out.  I have approached the problem different ways, such as width=x and length=2x+1 (using the 2L = 2S = P standard equation for finding perimeter), and w=1/7 P - 3, etc. for length, but I cannot come up with an actual answer.  Thanks in advance.\r<BR>\n" );
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document.write( "Maddie </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76220 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a couple of your equations have sign problems\r<BR>\n" );
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document.write( "let x=width\r<BR>\n" );
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document.write( "\"The length of a rectangle is 1 less than twice its width\" ... length=2x-1\r<BR>\n" );
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document.write( "\"the width is 3 more than one-seventh of the perimeter\" ... (p/7)+3=x ... p=7(x-3)\r<BR>\n" );
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document.write( "2(x)+2(2x-1)=7(x-3) </SPAN>\n" );
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