document.write( "Question 1141587: Alan wishes to dilute a mixture that is 10% alcohol to one that is 8% alcohol. How much 5% alcohol mixture should he add to 8 L of the 10% mixture? \n" ); document.write( "
Algebra.Com's Answer #762167 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1) Using the standard algebraic approach.... \n" ); document.write( "8 L of 10%, plus x L of 5%, equals 8% of (8+x) L: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: 16/3 L, or 5 1/3 L \n" ); document.write( "----------------------------------------------- \n" ); document.write( "A completely different method -- faster and easier, if you understand it.... \n" ); document.write( "You are going from 10% towards 5%; you are stopping at 8%. \n" ); document.write( "8 is 2/5 of the way from 10 to 5. (10-8=2; 10-5=5) \n" ); document.write( "That means 2/5 of the mixture is what you are adding; that means 3/5 of the mixture is what you started with; that means the amount you need to add is (2/5)/(3/5) = 2/3 of the amount you started with. \n" ); document.write( "ANSWER: (2/3)*8 = 16/3 L \n" ); document.write( " |