document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141593>Question 1141593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 20 and their difference is 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #762161 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=762161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "16 and 4.<br><BR>\n" );
document.write( "Picture the 20 and 12 on a number line.  The 20 is what you get when you ADD the second number to the first; the 12 is what you get when you SUBTRACT the second number from the first.<br><BR>\n" );
document.write( "That means the first number is halfway between 12 and 20 -- 16.  And so the second number is 4 (the difference between 16 and 20 or between 16 and 12).<br><BR>\n" );
document.write( "You see this kind of problem frequently; this is an easy way to solve them.<br><BR>\n" );
document.write( "If you need a formal algebraic solution...<br><BR>\n" );
document.write( "x+y = 20<BR>\n" );
document.write( "x-y = 12<br><BR>\n" );
document.write( "Solve by any of a number of basic methods. </SPAN>\n" );
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