document.write( "Question 1141562: A car company created a 90-second commercial and purchased enough air time for it to be played at 4 random times during prime time hours of 8p.m to 11 pm. If a viewer turns their television on at a random time during prime-time hours, what is the probability that the car commercial will be playing at the time?
\n" ); document.write( "A)1/120
\n" ); document.write( "B) 1/30
\n" ); document.write( "C) 1/45
\n" ); document.write( "D) 1/2
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Algebra.Com's Answer #762134 by ikleyn(52786)\"\" \"About 
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document.write( "The probability in this case is the ratio (the fraction) whose numerator is equal to 90*4 = 360 seconds,\r\n" );
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document.write( "while the denominator is 3 hours (the time from 8 pm to 11 pm), which is 3*3600 seconds.\r\n" );
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document.write( "So, the probability under the question is  \"360%2F%283%2A3600%29\" = \"1%2F%283%2A10%29\" = \"1%2F30\".\r\n" );
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document.write( "The answer is option B).\r\n" );
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