document.write( "Question 1141562: A car company created a 90-second commercial and purchased enough air time for it to be played at 4 random times during prime time hours of 8p.m to 11 pm. If a viewer turns their television on at a random time during prime-time hours, what is the probability that the car commercial will be playing at the time?
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document.write( "A)1/120
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document.write( "B) 1/30
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document.write( "C) 1/45
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document.write( "D) 1/2 \n" );
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Algebra.Com's Answer #762134 by ikleyn(52786)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "The probability in this case is the ratio (the fraction) whose numerator is equal to 90*4 = 360 seconds,\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "while the denominator is 3 hours (the time from 8 pm to 11 pm), which is 3*3600 seconds.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "So, the probability under the question is\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |