document.write( "Question 1141560: An office worker is allowed to take three 10-minute coffee breaks over the course a normal work day, which last from 9.am to 5p.m at randomly chosen times. If someone tried to ask the office worker at a random time during the work day, what is the probability that the worker will be on a coffee break?
\n" ); document.write( "A)1/6
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\n" ); document.write( "D)3/4
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Algebra.Com's Answer #762128 by ikleyn(52786)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "An office worker is allowed to take three 10-minute coffee breaks over the course a normal work day,
\n" ); document.write( "which \"highlight%28cross%28last%29%29\" lasts from 9.am to 5p.m at randomly chosen times.
\n" ); document.write( "If someone tried to ask the office worker at a random time during the work day, what is the probability
\n" ); document.write( "that the worker will be on a coffee break?
\n" ); document.write( "A)1/6
\n" ); document.write( "B) 1/8
\n" ); document.write( "C)1/4
\n" ); document.write( "D)3/4
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document.write( "The total duration of the three coffee breaks is 3*10 minutes = 30 minutes.\r\n" );
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document.write( "The total working day duration is 8 hours from 9 am to 5 pm,  or  8*60 = 480 minutes.\r\n" );
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document.write( "The probability under the question is  \"30%2F480\" = \"1%2F16\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "No one of the given options fits the answer -- but it is not my trouble -- it is YOUR trouble as a person
\n" ); document.write( "who posted incorrect answer options.\r
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