document.write( "Question 1141529: The product of two brothers' ages is 35. They are two years apart. How old are they?
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Algebra.Com's Answer #762100 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = the older brother's age
\n" ); document.write( "Let \"+b+\" = the younger brother's age
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\n" ); document.write( "(1) \"+a%2Ab+=+35+\"
\n" ); document.write( "(2) \"+a+-+b+=+2+\"
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\n" ); document.write( "(2) \"+a+=+b+%2B+2+\"
\n" ); document.write( "Plug this result into (1)
\n" ); document.write( "(1) \"+%28+b+%2B+2+%29%2Ab+=+35+\"
\n" ); document.write( "(1) \"+b%5E2+%2B+2b+-+35+=+0+\"
\n" ); document.write( "(1) \"+%28+b+%2B+7+%29%2A%28+b+-+5+%29+=+0+\" ( by looking at it )
\n" ); document.write( "\"+b+\" can't be negative, so
\n" ); document.write( "\"+b+=+5+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+a+=+b+%2B+2+\"
\n" ); document.write( "(2) \"+a+=+5+%2B+2+\"
\n" ); document.write( "(2) \"+a+=+7+\"
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\n" ); document.write( "The older brother is 7
\n" ); document.write( "The younger brother is 5
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