document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104688>Question 104688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor each polynomial completely<BR>\n" );
document.write( "-4w^3 - 16w^2 + 20w </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76210 by </B><A HREF=/tutors/aboutme.mpl?userid=TP><B>TP(29)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TP><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Looking at the polynomial we can see that 4w is a COMMON FACTOR and so<BR>\n" );
document.write( "-4w^3 - 16w^2 + 20w = 4w[-w^2 - 4w + 5]<BR>\n" );
document.write( "                    = -4w[w^2 + 4w - 5]<BR>\n" );
document.write( "Now to factorise w^2 + 4w - 5 we need to look for two numbers that when added together give you 4 and when multiplied together give you -5.<BR>\n" );
document.write( "These numbers are 5 and -1.<BR>\n" );
document.write( "So -4w[w^2 + 4w - 5] = -4w[(w + 5)(w-1)]ANS </SPAN>\n" );
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