document.write( "Question 1141202: A five digit number is formed using digits 0 1 2 3 and 4 without repetition. Find the chance that the number is divisible by 5. \n" ); document.write( "
Algebra.Com's Answer #762084 by ikleyn(52790)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "First, let us calculate the number of all possible five digit numbers formed using the digits 0, 1, 2, 3 and 4 without repetition.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The leftmost digit can be any of four digits 1, 2, 3 or 4, which gives 4 options.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The next digit can be any of 4 remaining digits, which gives 4 options.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Using similar arguments, you will get 4*4*3*2*1 = 96 for the number of all possible five digit numbers formed \r\n" ); document.write( "using the digits 0, 1, 2, 3 and 4 without repetition.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The numbers divisible by 10 are those of them that ended by 0 (by zero),\r\n" ); document.write( "and the number of such numbers is 4*3*2*1 = 24.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus the probability P under the question is the ratio \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " P =\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |