document.write( "Question 1141475: Suppose you work for an airline and you are taking reservations for a flight on an aircraft that has 152 seats. You know, based on historical flights trends, that if you sell a single ticket there is a 91% chance that the person with the ticket will actually show up for the flight. You decide to try to make a little extra money by overbooking your flight and you sell 160 tickets hoping that not more than 152 people will actually show up for the flight
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document.write( "Explain how this scenario meets the four requirements in the definition of a Binomial Distribution (page 200)\r
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document.write( "Identify what n and p are in this example \n" );
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Algebra.Com's Answer #762031 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! fixed n \n" ); document.write( "presumably independent probability of 0.91 here \n" ); document.write( "random sample \n" ); document.write( "two outcomes, show up or not. \n" ); document.write( "n=160 \n" ); document.write( "p=0.91 \n" ); document.write( "The mean is np \n" ); document.write( "the variance is np((1-p) \n" ); document.write( "the sd is sort (variance) \n" ); document.write( "there is no k. \n" ); document.write( "160, 0.91, 152 is what is inputted \n" ); document.write( "or \n" ); document.write( "Normal approximation \n" ); document.write( "mean is 145.6, sd is 3.62 \n" ); document.write( "z<(152-146)/3.62 \n" ); document.write( "z<1.66 \n" ); document.write( " |