document.write( "Question 1141476: Please help me solve this\r
\n" ); document.write( "\n" ); document.write( "Use the Binomial Theorem to expand (x-3y)^5
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Algebra.Com's Answer #762024 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The binomial theorem looks scary to most students when they first see it. But with a little experience it is fairly easy to use -- especially if you understand WHY it works.

\n" ); document.write( "So let me start you on this with a demonstration; then you can finish.

\n" ); document.write( "The expression means you have five identical factors of (x-3y). When you expand the expression, you are going to get terms of x^5, x^4y, x^3y^2, x^2y^3, xy^4, and y^5.

\n" ); document.write( "Think about how many ways you are going to get each of those kinds of terms.

\n" ); document.write( "(1) x^5...

\n" ); document.write( "To get an x^5 term, you clearly need to choose the \"x\" term from all 5 factors (and the \"-3y\" term in 0 of them). The number of ways you can choose the \"x\" term in all 5 of the 5 factors is \"5 choose 5\" = C(5,5) = 1.

\n" ); document.write( "So the x^5 term will be \"C%285%2C5%29%28%28x%29%5E5%29%28%28-3y%29%5E0%29+=+%281%29%28x%5E5%29%281%29+=+x%5E5\".

\n" ); document.write( "(2) x^4y...

\n" ); document.write( "To get an x^4y term, you need to choose the \"x\" term from 4 of the 5 factors and the \"-3y\" term in 1 of them. The number of ways you can choose the x term in 4 of the 5 factors is \"5 choose 4\" = C(5,4) = 5.

\n" ); document.write( "So the x^4y term will be \"C%285%2C4%29%28%28x%29%5E4%29%28%28-3y%29%5E1%29+=+%285%29%28x%5E4%29%28-3y%29+=+-15x%5E4y\".

\n" ); document.write( "(3) x^3y^2...

\n" ); document.write( "To get an x^3y^2 term, you need to choose the \"x\" term from 3 of the 5 factors and the \"-3y\" term in 2 of them. The number of ways you can choose the x term in 3 of the 5 factors is \"5 choose 3\" = C(5,3) = 10.

\n" ); document.write( "So the x^3y^2 term will be .

\n" ); document.write( "I'll let you fill in the calculations to finish the expansion. The remaining terms are

\n" ); document.write( "\"C%285%2C2%29%28%28x%29%5E2%29%28%28-3y%29%5E3%29\"

\n" ); document.write( "\"C%285%2C1%29%28%28x%29%5E1%29%28%28-3y%29%5E4%29\"

\n" ); document.write( "\"C%285%2C0%29%28%28x%29%5E0%29%28%28-3y%29%5E5%29\"

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