document.write( "Question 104710: x-2*sqrt(x-3)=3\r
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document.write( "solve for zero...\r
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document.write( "I subtract x from both sides which =\r
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document.write( "-2*sqrt(x-3)=3-x\r
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document.write( "then I divide by -2 from both sides\r
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document.write( "sqrt(x-3)=(3-x)/-2\r
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document.write( "then to get rid of the \"sqrt\" ^2 on both sides\r
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document.write( "x-3=(9+x^2)/4\r
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document.write( "then I subtract \"x\" and add 3 to both sides to solve for zero.\r
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document.write( "0=(9+x^2)/4-x+3\r
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document.write( "then I find a common denominator of 4 and solve\r
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document.write( "0=(9+x^2)/4 -4x/4+12/4 which equals 0=(x^2-4x+21)/4\r
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document.write( "then I multiply 4/1 on both side the loose the denominator.\r
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document.write( "0=x^2-4x+21 which can not be factored, but my text book gives a solution set of {7,3}. I cant find were I went wrong, please help.
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document.write( "Please note, this question had already been answered but the link to the answer did not work so this is why I am re-submitting it. Thank you. \n" );
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Algebra.Com's Answer #76202 by jim_thompson5910(35256)  You can put this solution on YOUR website! Start with the given equation\r \n" );
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document.write( " Subtract x from both sides\r \n" );
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document.write( " Divide both sides by -2\r \n" );
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document.write( " Square both sides\r \n" );
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document.write( "Now this is where you went wrong, when you square you need to foil it to get instead of \r \n" );
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document.write( " Foil the numerator and square the denominator\r \n" );
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document.write( " Add 3 to both sides\r \n" );
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document.write( " Multiply 3 by \r \n" );
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document.write( " Multiply \r \n" );
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document.write( " Add the fractions\r \n" );
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document.write( " Combine like terms\r \n" );
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document.write( " Multiply both sides by 4\r \n" );
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document.write( " Subtract 4x from both sides\r \n" );
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document.write( " Combine like terms\r \n" );
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document.write( " Rearrange the terms\r \n" );
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document.write( " Solved by pluggable solver: Quadratic Formula | \n" );
document.write( "Let's use the quadratic formula to solve for x:
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document.write( " Starting with the general quadratic \n" );
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document.write( "  \n" );
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document.write( " the general solution using the quadratic equation is: \n" );
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document.write( " So lets solve ( notice , , and ) \n" );
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document.write( " Plug in a=1, b=-10, and c=21 \n" );
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document.write( " Negate -10 to get 10 \n" );
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document.write( " Square -10 to get 100 (note: remember when you square -10, you must square the negative as well. This is because .) \n" );
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document.write( " Multiply to get  \n" );
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document.write( " Combine like terms in the radicand (everything under the square root) \n" );
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document.write( " Simplify the square root (note: If you need help with simplifying the square root, check out this solver) \n" );
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document.write( " Multiply 2 and 1 to get 2 \n" );
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document.write( " So now the expression breaks down into two parts \n" );
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document.write( " or  \n" );
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document.write( " Lets look at the first part: \n" );
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document.write( " Add the terms in the numerator \n" );
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document.write( " Divide \n" );
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document.write( " So one answer is \n" );
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document.write( " Now lets look at the second part: \n" );
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document.write( " Subtract the terms in the numerator \n" );
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document.write( " Divide \n" );
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document.write( " So another answer is \n" );
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document.write( " So our solutions are: \n" );
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document.write( " or  \n" );
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document.write( "So this means the solution set is {7,3} \n" );
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