document.write( "Question 1141427: Scores on a recent national statistics exam were normally distributed with a mean of 90 and a standard deviation of 5.
\n" ); document.write( "1.What is the probability that a randomly selected exam will have a score of at least 85?
\n" ); document.write( "2.What percentage of exams will have scores between 89 and 92?
\n" ); document.write( "3.If the top 2.5% of test scores receive merit awards, what is the lowest score eligible for an award?
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Algebra.Com's Answer #762013 by rothauserc(4718)\"\" \"About 
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Use the Normal distribution table of z-scores
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\n" ); document.write( "1. Probability(P) (X > 85) = 1 - P (X < 85)
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\n" ); document.write( "z-score = (85 - 90)/5 = -1
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\n" ); document.write( "P (X > 85) = 1 - 0.1587 = 0.8413
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\n" ); document.write( "the probability that a randomly selected exam will have a score of at least 85 is 0.8413
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\n" ); document.write( "2. P (89 < X < 92) = P (X < 92) - P (X < 89)
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\n" ); document.write( "z-score(92) = (92 - 90)/5 = 0.40
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\n" ); document.write( "z-score(89) = (89 - 90)/5 = -0.20
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\n" ); document.write( "P (89 < X < 92) = 0.6554 - 0.4207 = 0.2347
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\n" ); document.write( "percentage with scores between 89 and 92 is 23.47 %
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\n" ); document.write( "3. 1 - 0.025 = 0.975
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\n" ); document.write( "0.975 is associated with z-score of 1.96
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\n" ); document.write( "(X - 90)/5 = 1.96
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\n" ); document.write( "X - 90 = 9.8
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\n" ); document.write( "X = 99.8
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\n" ); document.write( "the lowest score eligible for an award is 99.8
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