document.write( "Question 104710: x-2*sqrt(x-3)=3\r
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document.write( "solve for zero...\r
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document.write( "I subtract x from both sides which =\r
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document.write( "-2*sqrt(x-3)=3-x\r
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document.write( "then I divide by -2 from both sides\r
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document.write( "sqrt(x-3)=(3-x)/-2\r
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document.write( "then to get rid of the \"sqrt\" ^2 on both sides\r
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document.write( "x-3=(9+x^2)/4\r
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document.write( "then I subtract \"x\" and add 3 to both sides to solve for zero.\r
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document.write( "0=(9+x^2)/4-x+3\r
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document.write( "then I find a common denominator of 4 and solve\r
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document.write( "0=(9+x^2)/4 -4x/4+12/4 which equals 0=(x^2-4x+21)/4\r
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document.write( "then I multiply 4/1 on both side the loose the denominator.\r
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document.write( "0=x^2-4x+21 which can not be factored, but my text book gives a solution set of {7,3}. I cant find were I went wrong, please help.
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document.write( "Please note, this question had already been answered but the link to the answer did not work so this is why I am re-submitting it. Thank you. \n" );
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Algebra.Com's Answer #76201 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Here's the step where you got on the wrong path. \n" ); document.write( " \n" ); document.write( "You're missing a term. \n" ); document.write( " \n" ); document.write( "Re-work \n" ); document.write( "You're on the right track otherwise. \n" ); document.write( "Post another question if you get stuck. \n" ); document.write( " |