document.write( "Question 1141444: How would I solve for x on this quadratic inequality? this is the one that's been puzzling me: (x+5)(x-2)(x-7)≤0\r
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Algebra.Com's Answer #761983 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "In the solution by tutor @mathlover1, she identified the values of x that make each of the individual factors negative or zero; but it is unclear how she used that information to identify the intervals on which the complete expression is negative or zero.

\n" ); document.write( "Consider the polynomial function

\n" ); document.write( "\"f%28x%29+=+%28x%2B5%29%28x-2%29%28x-7%29\"

\n" ); document.write( "We want to identify when the function value is zero or negative.

\n" ); document.write( "Clearly the function value is zero at x=-5, x=2, and x=7.

\n" ); document.write( "To identify the intervals on which the function value is negative, there are several options. Among those options are

\n" ); document.write( "(1) The function is a cubic with positive leading coefficient. Think of what the graph of that kind of function looks like. The function value is negative for \"large negative\" value of x and positive for large positive values of x. That, along with the known zeros of the function, will determine the intervals on which the function value is negative.

\n" ); document.write( "(2) Choose a test point in each of the intervals determined by the zeros of the function to see whether the function value is positive or negative in each interval.

\n" ); document.write( "(3) (My personal choice....) You know that for large negative values of x all three factors are negative, so the function value is negative to the left of x=-5. Then, as you \"walk\" along the number line to the right, the function value changes sign each time you pass one of the zeros. So the function value is (a) negative for x less than -5; (b) positive for x between -5 and 2; (c) negative for x between 2 and 7; and (d) positive for x greater than 7.
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