document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141377>Question 1141377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Beth can travel 208 miles in the same time it takes Anna to travel 192 miles. If Beth's speed is 4 mph greater than Anna's, find both rates. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761920 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Anna travels at x mph and takes xt hours to go 192 miles<BR>\n" );
document.write( "Beth travels at (x+4) mph and takes xt hours to go 208 miles<BR>\n" );
document.write( "t for Anna is 192/x<BR>\n" );
document.write( "t for Beth is 208/(x+4)<BR>\n" );
document.write( "those t s are equal, so that (192/x)=208/(x+4)<BR>\n" );
document.write( "cross multiply so that 192x+768=208cx<BR>\n" );
document.write( "16x=768<BR>\n" );
document.write( "x=48 mph for Anna<BR>\n" );
document.write( "x+4=52 mph for Beth<BR>\n" );
document.write( "4 hours will be t. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );