document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141324>Question 1141324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sector with a radius of 2.25m and sector angle 56.<BR>\n" );
document.write( "calculate area of the sector </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761845 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761845\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of the whole circle is pi*2.25^2m=15.90 m^2<BR>\n" );
document.write( "56 degrees is 56/360 of the whole area, so multiply that fraction by 15.90=2.47 m^2. </SPAN>\n" );
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