document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141292>Question 1141292</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find the equilibrium point (at which s=d) if the demand (d) is given by d=200/p and the supply is given by s=150p-200? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761817 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d=s<BR>\n" );
document.write( "so 200/p =150p-200<BR>\n" );
document.write( "multiply by p both sides<BR>\n" );
document.write( "200=150p^2-200p<BR>\n" );
document.write( "rewrite as 150p^2-200p-200=0<BR>\n" );
document.write( "divide everything by 50<BR>\n" );
document.write( "3p^2-4p-4=0<BR>\n" );
document.write( "(3p+2)(p-2)=0<BR>\n" );
document.write( "p=2, only positive root<BR>\n" );
document.write( "so at p=2, d=100 and s=100 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );