document.write( "Question 1141190: A random sample of 250 adults found that 67% of them access the internet at work, 82% of them access the internet at home and 60% access the internet both at home and work. What is the probability that a randomly selected adult will access the internet at home or at work? \n" ); document.write( "

Algebra.Com's Answer #761800 by VFBundy(438) $\"\"$ $\"About$

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P(home or work) = P(home) + P(work) - P(home and work)
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\n" ); document.write( "P(home or work) = 82% + 67% - 60% = 89%
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