document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141260>Question 1141260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ) According to a certain​ survey, adults spend <BR>\n" );
document.write( "2.45<BR>\n" );
document.write( "2.45 hours per day watching television on a weekday. Assume that the standard deviation for​ \"time spent watching television on a​ weekday\" is <BR>\n" );
document.write( "1.93<BR>\n" );
document.write( "1.93 hours. If a random sample of <BR>\n" );
document.write( "60<BR>\n" );
document.write( "60 adults is​ obtained, describe the sampling distribution of <BR>\n" );
document.write( "x overbar<BR>\n" );
document.write( "x​, the mean amount of time spent watching television on a weekday. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761772 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sampling distribution of 60 adults has the same mean as the sample, 2.45 hours/day<BR>\n" );
document.write( "The sd of that distribution is 1.93/ sort (60), the sample size, or 0.25 hours.<BR>\n" );
document.write( "X bar ~N(1.93, 0.25) units hours </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );