document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141253>Question 1141253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You choose a tile at random from a bag containing 2A's, 3B's, and 4C's.  You replace the first tile in the bag and then choose again.  Find each probability.<BR>\n" );
document.write( "P(A and A)<BR>\n" );
document.write( "P(A and B)<BR>\n" );
document.write( "P(B and C) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761760 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761760\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 9 tiles in the bag<BR>\n" );
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document.write( "P(A and A) = (2/9) * (2/9) = 4/81<BR>\n" );
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document.write( "P(A and B) = (2/9) * (3/9) = 6/81 = 2/27<BR>\n" );
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document.write( "P(B and C) = (3/9) * (4/9) = 12/81 = 4/27<BR>\n" );
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document.write( "  </SPAN>\n" );
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