document.write( "Question 1141232: a regular pentagon ABCDE is inscribe in a circle, centre O. calculate angle ABD. well explain with the diagram
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Algebra.Com's Answer #761755 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Angle B, an interior angle of a regular pentagon, is 108 degrees.

\n" ); document.write( "Angles ABE and CBD, being base angles in isosceles triangles with vertex angles of 108 degrees, are each 36 degrees.

\n" ); document.write( "That makes angle EBD 36 degrees.

\n" ); document.write( "Then angle ABD is angle ABE plus angle EBD, which is 36+36 = 72 degrees.
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