document.write( "Question 1141192: A travel agent wants to estimate the mean price of a flight from Boston to Denver. A different airline study show that the standard deviation of flight tickets is $56.92. The agent wants her estimate to be within $25 of the true mean flight cost. How many flights must she include in her sample in order to be 90% in her estimate? \n" ); document.write( "
Algebra.Com's Answer #761741 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the critical z-score at 90% confidence level is plus or minus 1.645.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score formula is z = (x - m) / s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z is the z-score. \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard error.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for s is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "s = standard deviation / square root of sample size = sd / sqrt(n).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for the score to be within 25 of the mean, then (x - m) must be equal to plus or minus 25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we'll work the plus side.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the minus side should give you the same answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (x - m) / s becomes 1.645 = 25 / s which becomes 25 / (56.92/sqrt(n))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get 1.645 = 25 * sqrt(n) / 56.92\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for sqrt(n) to get sqrt(n) = 1.645 * 56.92 / 25 = 3.745336.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for n to get n = 3.745336 ^ 2 = 14.02754175.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when the sample size is 14.02754175, s = sd / sqrt(n) becomes s = 56.92 / sqrt(14.02754175) = 15.19756839.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when z = 1.645, the z-score formula of z = (x - m) / s becomes 1.645 = (x - m) / 15.19756839.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for (x - m) to get (x - m) = 1.645 * 15.19756839) = 25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the z-score is -1.645, then z = (x - m) / s becomes -1.645 = (x - m) / 15.19756839 and you get (x - m) = -1.645 * 15.19756839 = -25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x - m = 25, then x = m + 25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x - m = -25, then x = m - 25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your score will be within 25 dollars of the mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the mean could be anything and the formula will get you within 25 dollars of the mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example, let the mean be 100 dollars.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at the 90% confidence level, the z-score is plus or minus 1.645.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the positive z-score formula becomes 1.645 = (x - 100) / 15.19756839.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = 1.645 * 15.19756839 + 100 = 125.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the negative z-score formula becomes -1.645 = (x - 100) / 15.19756839.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = -1.645 * 15.19756839 + 100 = 75.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "125 is 25 dollars from the mean of 100. \n" ); document.write( "75 is 25 dollars from the mean of 100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can substitute any other mean and you will get the same distance from the mean, i.e. 25 dollars plus or minus from the mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to be exact, the sample size needed to be 14.02754175.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "however, the number of flights is not a fraction, therefore you would go to the next higher integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "she must include at least 15 flights to be 25 dollars or less from the true mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the following excel spreadsheet shows some of the figures from 10 to 20 flights in the sample size, including the one where we calculated 14.02754175.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |