document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141045>Question 1141045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Point is the point (2,5) and Q is (6,0).<BR>\n" );
document.write( "A line L is drawn through P perpendicular to PQ to meet the y-axis at point R.<BR>\n" );
document.write( "1) Find the equation of line L<BR>\n" );
document.write( "2) Find the coordinates of point R<BR>\n" );
document.write( "3) Find the area of triangle OPR </SPAN>\n" );
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document.write( "1) equation of line L<br><BR>\n" );
document.write( "The slope of the line through P and Q is -5/4; the slope of a line perpendicular to that line is 4/5.  Given a perpendicular through P, you have a point and a slope which you can use with either the slope-intercept or point-slope form of a linear equation to find the equation of line L.<br><BR>\n" );
document.write( "2) coordinates of point R (x-intercept of line L)<br><BR>\n" );
document.write( "In the equation from part 1, set y=0 and solve for x.<br><BR>\n" );
document.write( "3) area of triangle QPR (not OPR)<br><BR>\n" );
document.write( "The base is QR; since QR is on the x-axis, the height of the triangle is the y coordinate of P.  Use area = one-half base times height. </SPAN>\n" );
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