document.write( "Question 1141174: A boy has five blue marbles, four green marbles and three red marbles. In
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Algebra.Com's Answer #761703 by Edwin McCravy(20055)\"\" \"About 
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A boy has five blue marbles, four green marbles and three red marbles. In
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document.write( "There are enough blue marbles to have BBBB.\r\n" );
document.write( "There are enough green marbles to have GGGG.\r\n" );
document.write( "If there were enough red marbles to have RRRR, then the answer would \r\n" );
document.write( "be achieved this way:\r\n" );
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document.write( "3 choices of color for the 1st marble, \r\n" );
document.write( "3 choices of color for the 2nd marble, \r\n" );
document.write( "3 choices of color for the 3rd marble, and\r\n" );
document.write( "3 choices of color for the 4th marble. \r\n" );
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document.write( "That would be 3∙3∙3∙3 = 34 = 81 ways.\r\n" );
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document.write( "However there are NOT enough red marbles to have RRRR.\r\n" );
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document.write( "So RRRR is the ONLY case of the 81 that we can't have,\r\n" );
document.write( "because none of the others can contain more than 3 R's.\r\n" );
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document.write( "So we subtract 1 from the 81:\r\n" );
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document.write( "Answer: 80\r\n" );
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document.write( "Edwin
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