document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141163>Question 1141163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You want to estimate the mean time college students spend watching online videos each day.  The estimate must be within 1 minute of the population mean, and you want to be 99% confident in your estimate.  What sample size would be required if the standard deviation of viewing time is 2.4 minutes? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761696 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> error is 1 minute=z*sigma/sqrt(n)=2.576*2.4/sqrt(n)<BR>\n" );
document.write( "square both sides and multiply through by n<BR>\n" );
document.write( "1n=38.22<BR>\n" );
document.write( "39 people.<BR>\n" );
document.write( " </SPAN>\n" );
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