document.write( "Question 1141138: Jane left the school and started to bike along the road at a rate of 12 mph. Her friend Sally left the school 10 minutes after Jane, biking on the same road at a rate of 15 mph. How long will it take Sally to catch up with Jane?
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Algebra.Com's Answer #761668 by josgarithmetic(39621)\"\" \"About 
You can put this solution on YOUR website!
Jane: \"12%2A%281%2F6%29=2\"\"miles\"\r
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\n" ); document.write( "\n" ); document.write( "Sally: approach rate is \"15-12=3\"\"mph\"\r
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\n" ); document.write( "\n" ); document.write( "Catch up:
\n" ); document.write( "\"3%28miles%2Fhour%29%2Ax%28hours%29=2%2Amiles\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2%2F3\"
\n" ); document.write( "FORTY MINUTES\r
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