document.write( "Question 104663: x-2*sqrt(x-3)=3\r
\n" ); document.write( "\n" ); document.write( "solve for zero...\r
\n" ); document.write( "\n" ); document.write( "I subtract x from both sides which =\r
\n" ); document.write( "\n" ); document.write( "-2*sqrt(x-3)=3-x\r
\n" ); document.write( "\n" ); document.write( "then I divide by -2 from both sides\r
\n" ); document.write( "\n" ); document.write( "sqrt(x-3)=(3-x)/-2\r
\n" ); document.write( "\n" ); document.write( "then to get rid of the \"sqrt\" ^2 on both sides\r
\n" ); document.write( "\n" ); document.write( "x-3=(9+x^2)/4\r
\n" ); document.write( "\n" ); document.write( "then I subtract \"x\" and add 3 to both sides to solve for zero.\r
\n" ); document.write( "\n" ); document.write( "0=(9+x^2)/4-x+3\r
\n" ); document.write( "\n" ); document.write( "then I find a common denominator of 4 and solve\r
\n" ); document.write( "\n" ); document.write( "0=(9+x^2)/4 -4x/4+12/4 which equals 0=(x^2-4x+21)/4\r
\n" ); document.write( "\n" ); document.write( "then I multiply 4/1 on both side the loose the denominator.\r
\n" ); document.write( "\n" ); document.write( "0=x^2-4x+21 which can not be factored, but my text book gives a solution set of {7,3}. I cant find were I went wrong, please help
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Algebra.Com's Answer #76166 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
x-2*sqrt(x-3)=3
\n" ); document.write( "solve for zero...
\n" ); document.write( "------------------
\n" ); document.write( "x-2*sqrt(x-3)=3
\n" ); document.write( "solve for zero...
\n" ); document.write( "-2sqrt(x-3) = 3-x
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "4(x-3) = 9-6x+x^2
\n" ); document.write( "4x-12 = 9-6x+x^2
\n" ); document.write( "x^2-10x+21=0
\n" ); document.write( "(x-3)(x-7)=0
\n" ); document.write( "x = 3 or x=7
\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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