document.write( "Question 104663: x-2*sqrt(x-3)=3\r
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document.write( "solve for zero...\r
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document.write( "I subtract x from both sides which =\r
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document.write( "-2*sqrt(x-3)=3-x\r
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document.write( "then I divide by -2 from both sides\r
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document.write( "sqrt(x-3)=(3-x)/-2\r
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document.write( "then to get rid of the \"sqrt\" ^2 on both sides\r
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document.write( "x-3=(9+x^2)/4\r
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document.write( "then I subtract \"x\" and add 3 to both sides to solve for zero.\r
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document.write( "0=(9+x^2)/4-x+3\r
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document.write( "then I find a common denominator of 4 and solve\r
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document.write( "0=(9+x^2)/4 -4x/4+12/4 which equals 0=(x^2-4x+21)/4\r
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document.write( "then I multiply 4/1 on both side the loose the denominator.\r
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document.write( "0=x^2-4x+21 which can not be factored, but my text book gives a solution set of {7,3}. I cant find were I went wrong, please help \n" );
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Algebra.Com's Answer #76166 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! x-2*sqrt(x-3)=3 \n" ); document.write( "solve for zero... \n" ); document.write( "------------------ \n" ); document.write( "x-2*sqrt(x-3)=3 \n" ); document.write( "solve for zero... \n" ); document.write( "-2sqrt(x-3) = 3-x \n" ); document.write( "Square both sides to get: \n" ); document.write( "4(x-3) = 9-6x+x^2 \n" ); document.write( "4x-12 = 9-6x+x^2 \n" ); document.write( "x^2-10x+21=0 \n" ); document.write( "(x-3)(x-7)=0 \n" ); document.write( "x = 3 or x=7 \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |