document.write( "Question 1141075: twice carry's age, added to sam's age, gives you a total of 20. if 3 times carry's age is subracted from twice sam's age, the result is 3 times carry's age, increased by 10. how old is each \n" ); document.write( "
Algebra.Com's Answer #761619 by ankor@dixie-net.com(22740)\"\" \"About 
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c = Carryy's present age
\n" ); document.write( "s = Sam's age
\n" ); document.write( ":
\n" ); document.write( "twice carry's age, added to sam's age, gives you a total of 20.
\n" ); document.write( "2c + s = 20
\n" ); document.write( " if 3 times carry's age is subtracted from twice sam's age, the result is 3 times carry's age, increased by 10.
\n" ); document.write( "2s - 3c = 3c + 10
\n" ); document.write( "2s - 3c - 3c = 10
\n" ); document.write( "2s - 6c = 10
\n" ); document.write( ":
\n" ); document.write( "multiply the first equation by 2 and rearrange, subtract the above equation
\n" ); document.write( "2s + 4c = 40
\n" ); document.write( "2s - 6c = 10
\n" ); document.write( "-----------------
\n" ); document.write( "0 + 10c = 30
\n" ); document.write( "c = 30/10
\n" ); document.write( "c = 3 yrs is Carry's age
\n" ); document.write( "Find s
\n" ); document.write( "2s - 6(3) = 10
\n" ); document.write( "2s = 10 + 18
\n" ); document.write( "2s = 28
\n" ); document.write( "s = 28/2
\n" ); document.write( "s = 14 yrs is Sam's age
\n" ); document.write( ":\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "check solution in statement
\n" ); document.write( "\"if 3 times carry's age is subracted from twice sam's age, the result is 3 times carry's age, increased by 10. \"
\n" ); document.write( "2(14) - 3(3) = 3(3) + 10
\n" ); document.write( "28 - 9 = 9 + 10
\n" ); document.write( "28 = 9 + 9 + 10
\n" ); document.write( "28 = 28 \n" ); document.write( "
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