document.write( "Question 1141069: Jordan has invested $4000 in an account that earns 3.6% compounded annually. Approximately how many years will it take for his money to double \n" ); document.write( "
Algebra.Com's Answer #761611 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Compounded ANNUALLY.\r
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\n" ); document.write( "\n" ); document.write( "\"1.036%5E1=1.036\"
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\n" ); document.write( "\"1.036%5E2=1.0733\"
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\n" ); document.write( "\"1.036%5E4=1.15196\"
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\n" ); document.write( "\"1.036%5E8=1.327\"
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\n" ); document.write( "\"1.036%5E11=1.476\"
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\n" ); document.write( "\"highlight%28n=20%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"1.036%5E20=2.029\"\r
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\n" ); document.write( "\"2=1.036%5En\"
\n" ); document.write( "\"log%28%282%29%29=n%2Alog%28%281.036%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"n=log%28%282%29%29%2Flog%28%281.036%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"n=19.60\", close to 20 is better.
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