document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15384>Question 15384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The rectangle has a perimeter of 78 centimeters.the length of the rectangle is 11 centimeters longer than triple the width. Find the demensions of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7616 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = width<BR>\n" );
document.write( "3x +11 = length\r<BR>\n" );
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document.write( "2(x) + 2(3x+11) = 78<BR>\n" );
document.write( "2x + 6x + 22 = 78<BR>\n" );
document.write( "8x + 22 = 78<BR>\n" );
document.write( "8x + 22 - 22 = 78 - 22<BR>\n" );
document.write( "8x = 56<BR>\n" );
document.write( "x= 7  Width<BR>\n" );
document.write( "3x+11 = 3(7) + 11 = 32  Length\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "2(7) + 2(32)= 78<BR>\n" );
document.write( "14 + 64 = 78<BR>\n" );
document.write( "It checks!\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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