document.write( "Question 1141004: I have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a hat, then from that hat, I choose 3 balls, without replacing the balls between selections. How many different ordered selections of 3 balls are possible?\r
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document.write( "I made my solution and tell me if it's correct or not. But if any mistakes are to be found, I'd like to ask for clarifications. So, here's my solution:\r
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document.write( "2(15P3 + 9P3)
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document.write( "since there are two hats there's going to be 2 ways. And for that, since there are two cases to choose either we could have the first hat from 1 through 15 or
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document.write( "16 through 25 where either we get 3 from the 1st or 2nd - we then add it. Since without replacement, we could say that the number is to be reduce from succeeding stages(say 15,14,13 or in a manner of 15P3, in the first hat and same thing with the second hat).\r
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document.write( "For the answer, I get 6468 ordered selections.\r
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Algebra.Com's Answer #761546 by ikleyn(52817)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "15P3 + 9P3.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "You do not need to double it.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |