document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140964>Question 1140964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me!<BR>\n" );
document.write( "Triangle ABC is formed by the points A(2,0), B(4,-4) and C(-2,-2). Prove using a property of<BR>\n" );
document.write( "linear relations that this is a right triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761507 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Look at the slopes of any two of the points and see if they are a negative reciprocal, which would mean perpendicular<BR>\n" );
document.write( "AB has slope of -4/2<BR>\n" );
document.write( "BC has slope of 2/-6 or -1/3<BR>\n" );
document.write( "CA has slope of -2/-4 or +1/2<BR>\n" );
document.write( "AB and CA have a negative reciprocal slope so perpendicular.\r<BR>\n" );
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document.write( "One can also use the distance formula for <BR>\n" );
document.write( "AB sqrt(4+16)<BR>\n" );
document.write( "BC sqrt (36+4)<BR>\n" );
document.write( "CA sqrt (4+16)<BR>\n" );
document.write( "sum of the sqrts is 20+20=40, and that is a right triangle as well. </SPAN>\n" );
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