document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140903>Question 1140903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I am to solve for x, then what would be the solution to this rational expression?\r<BR>\n" );
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document.write( "The following expression: https://i.imgur.com/xaauike.png </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761464 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761464\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1+(4/(x+1))=-8/(x^2-1).  Common denominator is x^2-1 or (x+1)(x-1)<BR>\n" );
document.write( "numerator is x^2-1+4(x-1)=-8, and we can ignore the denominator, since it is the same for all<BR>\n" );
document.write( "x^2+4x-5=-8 or x^2+4x+3=0<BR>\n" );
document.write( "(x+1)(x+3)=0<BR>\n" );
document.write( "x=-1, -3<BR>\n" );
document.write( "If x=-1, the denominator of the second term on the left and the right term is 0, so this is an extraneous root.<BR>\n" );
document.write( "if x=-3<BR>\n" );
document.write( "1+(4/-2)=-(8/8)<BR>\n" );
document.write( "1-2=-1, checks<BR>\n" );
document.write( "answer is x=-3<BR>\n" );
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